<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:content="http://purl.org/rss/1.0/modules/content/"><channel><title>Random Events</title><link>https://hugomvale.github.io/random-events/</link><description>Recent content on Random Events</description><generator>Hugo</generator><language>en-us</language><lastBuildDate>Thu, 06 Aug 2026 00:00:00 +0000</lastBuildDate><atom:link href="https://hugomvale.github.io/random-events/index.xml" rel="self" type="application/rss+xml"/><item><title>Double or Nothing</title><link>https://hugomvale.github.io/random-events/posts/double-or-nothing/</link><pubDate>Thu, 06 Aug 2026 00:00:00 +0000</pubDate><guid>https://hugomvale.github.io/random-events/posts/double-or-nothing/</guid><description>&lt;p&gt;Consider an elementary reaction in which a reactant $\mathrm{A}$ reacts with itself to produce a product $\mathrm{P}$:&lt;/p&gt;
$$ \mathrm{A} + \mathrm{A} \xrightarrow{} \mathrm{P} $$&lt;p&gt;with rate coefficient $k$. The rate of consumption of $\mathrm{A}$ is then:&lt;/p&gt;
$$ - \frac{\mathrm{d}[\mathrm{A}]}{\mathrm{d}t} = 2 k [\mathrm{A}]^2 $$&lt;p&gt;Now suppose we add another reactant $\mathrm{B}$, with similar reactivity to $\mathrm{A}$. In this new scenario, $\mathrm{A}$ can also react with B:&lt;/p&gt;
$$ \mathrm{A} + \mathrm{B} \xrightarrow{} \mathrm{R} $$&lt;p&gt;Since this additional reaction step consumes a single $\mathrm{A}$ molecule, and since $\mathrm{A}$ and $\mathrm{B}$ have similar reactivity, one might be tempted to write:&lt;/p&gt;</description></item><item><title>Waves Under Tension</title><link>https://hugomvale.github.io/random-events/posts/waves-tension/</link><pubDate>Wed, 05 Aug 2026 00:00:00 +0000</pubDate><guid>https://hugomvale.github.io/random-events/posts/waves-tension/</guid><description>&lt;p&gt;Knowing very little about music, acoustics, or wave mechanics, I couldn&amp;rsquo;t help being impressed by this &lt;a href="https://www.youtube.com/watch?v=YlPTasQsPo8"&gt;Christmas Lectures video&lt;/a&gt;, especially the Chladni figures.&lt;/p&gt;
&lt;p&gt;The urge to calculate those patterns was almost immediate. The problem was that, although I was already somewhat familiar with hyperbolic conservation equations, waves are a rather different beast. So I had to start from the very beginning.&lt;/p&gt;
&lt;p&gt;The simplest wave model is the one-dimensional wave equation:&lt;/p&gt;
$$
\frac{\partial^2 u}{\partial t^2} =
c^2 \frac{\partial^2 u}{\partial x^2}
$$&lt;p&gt;This equation describes, for example, the vibration of a guitar string, the propagation of seismic waves during an earthquake, or the pressure fluctuations that allow us to enjoy our favorite song.&lt;/p&gt;</description></item><item><title>A Diacid Paradox</title><link>https://hugomvale.github.io/random-events/posts/equilibrium-diacid/</link><pubDate>Sun, 26 Jul 2026 00:00:00 +0000</pubDate><guid>https://hugomvale.github.io/random-events/posts/equilibrium-diacid/</guid><description>&lt;p&gt;Suppose we have a weak mono-acid $\mathrm{HA}$ and a diacid $\mathrm{H_2D}$ that is, in all chemical respects, similar to $\mathrm{HA}$, except that it has two acid groups so far apart that they do not interact. How do the acid dissociation constants of $\mathrm{H_2D}$ relate to that of $\mathrm{HA}$?&lt;/p&gt;
&lt;p align="center"&gt;
&lt;img src="equilibrium-diacid.png" alt="Mono-acid and di-acid" style="max-width: 450px; width:
100%;"&gt;
&lt;/p&gt;
&lt;p align="center"&gt;&lt;em&gt;A mono carboxylic acid and a chemically similar di-acid.&lt;/em&gt;&lt;/p&gt;
&lt;p&gt;Certainly, since the two acid groups are identical, we might expect:&lt;/p&gt;</description></item><item><title>The Case of the 3-Hole Can</title><link>https://hugomvale.github.io/random-events/posts/can-3-holes/</link><pubDate>Sat, 25 Jul 2026 00:00:00 +0000</pubDate><guid>https://hugomvale.github.io/random-events/posts/can-3-holes/</guid><description>&lt;p&gt;The other day, I saw this &lt;a href="https://www.youtube.com/watch?v=4wa8IKMYwK8&amp;amp;t=1080s"&gt;video&lt;/a&gt; from Prof. Julius Sumner Miller and was immediately &lt;em&gt;enchanted&lt;/em&gt; by the question:&lt;/p&gt;
&lt;blockquote&gt;
&lt;p&gt;How does the water come out of a tall can in which three holes reside?&lt;/p&gt;
&lt;/blockquote&gt;
&lt;p&gt;I knew how the efflux velocity depends on the height of the liquid, but I didn&amp;rsquo;t have a clue about the distance it would travel.&lt;/p&gt;
&lt;p&gt;So, here is the solution.&lt;/p&gt;
&lt;p align="center"&gt;
&lt;img src="schematic.png" alt="Schematic" style="max-width: 450px; width:
100%;"&gt;
&lt;/p&gt;
&lt;p align="center"&gt;&lt;em&gt;The path of the water from a tall can.&lt;/em&gt;&lt;/p&gt;</description></item></channel></rss>